Question

factorise (x+2)^2-(x+4)^2​

Answer 1

$x ^{2} + 2x \times 2 + 2 ^{2} - (x + 4) ^{2}$

$x ^{2} + 2x \times 2 + 2 ^{2} - (x ^{2} + 2x \times 4 + 4^{2} )$

$x ^{2} + 2x \times 2 + 2 ^{2} - x - ^{2} - 2x \times 4 - 4 ^{2}$

$x ^{2} + 2x \times 2 + 4 - x {2} - 2x \times 4 - 4 ^{2}$

$x^{2} + 2x \times 2 + 4 - x ^{2} - 2x \times 4 - 16$

$x ^{2} + 4x + 4 - x{2} - 8x - 16$

$(x ^{2} - x ^{2} ) + (4x - 8x) + (4 - 16)$

$- 4x - 12$

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