Question

factorise x^2-22x+120​

Answer 1

Answer= (x-10)(x-12).

Answer 2

${x}^{2} - 22x + 120 = 0 \\ \\ {x}^{2} - 12x - 10x + 120 = 0 \\ \\ x(x - 12) - 10(x - 12) = 0 \\ \\ (x - 12)(x - 10) = 0 \\ \\ x - 12 = 0 \\ x = 12 \\ \\ x - 10 = 0 \\ x = 10$

Hence the values of x are 12 & 10.

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