Question

factorise x^2+√2x-24​

Answer 1

Answer:

-4√2 and 3√2 are the roots of the x^2+√2x-24.

Step-by-step explanation:

The first term is,  x2  its coefficient is  1 .

The middle term is,  √2x  its coefficient is  √2 .

The last term, "the constant", is  -24 .

Multiply the coefficient of the first term by the constant .

So,1×-24=-24.

Find the factors of -24 whose sum = √2 .

The sum of( -3√2+4√2=√2). And their product is -24.

Rewrite the polynomial splitting the middle term using the two factors found above.

x^2 -3√2x+4√2x-24=0

x(x-3√2) 4√2(x-3√2)=0

(x+4√2)(x-3√2)=0.

x+4√2=0 (or) x-3√2=0

x=-4√2 (or) x=3√2.

Therefore -4√2 and 3√2 are the roots of the x^2+√2x-24.