factorise x^2–2xy+y^2–2(x–y)+1
Answers
Answered by
0
Answer:Using the identity:
x2+y2−2xy=(x−y)2
x2+y2−2xy−1=(x−y)2−1=(x−y−1)∗(x−y+1)
We therefore have 2 factors: (x−y−1) and (x−y+1)
Step-by-step explanation:
Similar questions