factorise x^2 +2xy+y^2-a^2+2ab-b^2
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Answered by
20
(x²+2xy+y²) - (a²-2ab+b²)
Since a²-2ab+b²= (a-b)²
= (x+y)²-(a-b)²
Let (x+y) be m and (a-b) be n
m²-n²= (m+n)(m-n)
= (x+y+(a-b)) ( x+y-(a-b))
= (x+y+a-b) (x+y-a+b)
Since a²-2ab+b²= (a-b)²
= (x+y)²-(a-b)²
Let (x+y) be m and (a-b) be n
m²-n²= (m+n)(m-n)
= (x+y+(a-b)) ( x+y-(a-b))
= (x+y+a-b) (x+y-a+b)
Answered by
14
Hey !
Here is your answer !!
___________
▶(x2 + y2 + 2xy)- ( a2 + b2 - 2ab )
▶ (x + y)2 - (a - b)2
Using the formula - a2 - b2 = (a+b) (a - b)
(x + y + a - b ) ( x + y - ( a - b )
( x + y + a - b ) ( x + y - a + b )
hope it helps :)
Here is your answer !!
___________
▶(x2 + y2 + 2xy)- ( a2 + b2 - 2ab )
▶ (x + y)2 - (a - b)2
Using the formula - a2 - b2 = (a+b) (a - b)
(x + y + a - b ) ( x + y - ( a - b )
( x + y + a - b ) ( x + y - a + b )
hope it helps :)
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