factorize 3 x cube minus x square - 3 x + 1
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Answered by
167
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HERE IS UR ANSWER --
3x^3 - x^2 - 3x + 1
= x^2 ( 3x - 1 ) - 1 ( 3x - 1 )
= ( 3x - 1 ) ( x^2 - 1 )
= ( 3x - 1 ) [ (x)^2 - (1)^2 ]
= ( 3x - 1 ) [ (x + 1) (x - 1)]
HERE IS UR ANSWER --
3x^3 - x^2 - 3x + 1
= x^2 ( 3x - 1 ) - 1 ( 3x - 1 )
= ( 3x - 1 ) ( x^2 - 1 )
= ( 3x - 1 ) [ (x)^2 - (1)^2 ]
= ( 3x - 1 ) [ (x + 1) (x - 1)]
Answered by
93
3x³ - x² - 3x + 1
This can be factorized by grouping the terms.
Here, to factorize, we have to group 3x³ and x² and also 3x and 1
3x³ - x² - 3x + 1
x² (3x - 1) - 1 (3x - 1)
(3x - 1) (x² - 1)
Here, again x² - 1 is in the form of a² - b²
a² - b² = (a + b) (a - b)
So
(3x - 1) (x + 1) (x - 1) is the factorization.
Hope this helps you.
This can be factorized by grouping the terms.
Here, to factorize, we have to group 3x³ and x² and also 3x and 1
3x³ - x² - 3x + 1
x² (3x - 1) - 1 (3x - 1)
(3x - 1) (x² - 1)
Here, again x² - 1 is in the form of a² - b²
a² - b² = (a + b) (a - b)
So
(3x - 1) (x + 1) (x - 1) is the factorization.
Hope this helps you.
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