factorise (x^2-2xy)+(z^2-2yz)
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Step-by-step explanation:
- Given Factorise (x^2-2xy)+(z^2-2yz)
- We need to factorise the given equation.
- Given (x^2 – 2xy) + (z^2 – 2yz)
- Taking common factor we get
- So x(x – 2y) + z(z – 2y)
- If the question is 2x – 2xy + 2yz – z^2 we get
- -2xy + 2x + 2yz – 2z
- -2xy + 2x
- = 2x (1 – y) + 2yz – 2z
- = - 2z (1 – y)
So (2x – 2z) (1 – y)
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Answer:
(x - z ) ( x - 2y + z ) is the correct answer...
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