Question

Factorise (x^2-2y)^2+22(x^2-2y)+96

Answer 1

(x²-2y)²+22(x²-2y)+96

= (x²-2y)+(16+6)(x²-2y)+(16)(6)

= (x²-2y+16)(x²-2y+6).

Answer 2

Answer:

Step-by-step explanation:

(x²-2y)²+22(x²-2y)+96

= (x²-2y)+(16+6)(x²-2y)+(16)(6)

= (x²-2y+16)(x²-2y+6).