Math, asked by DRAGONITR, 1 year ago

factorise x^2+3√2x+4

Answers

Answered by Anonymous
125
x²+3√2x+4
BY splitting the mid term ,

x²+2√2x+√2x+4
x(x+2√2)+√2(x+2√2)

(x+2√2)(x+√2)

hope this helps
any confusion then inbox me

DRAGONITR: thanks a lot
Anonymous: ur welcome
Answered by amirgraveiens
42

x^2+3√2x+4=(x+√2)(x+2√2)

Step-by-step explanation:

Given:

x^2+3\sqrt{2}x+4

Now the first step will be that we will split the middle term therefore,

=x^2+2\sqrt{2}x+\sqrt{2}x+4

=x^2 +2\sqrt{2}x+\sqrt{2}x + 2\sqrt{2\times2}          [2\sqrt{2\times2}=2\times2=4]

=x^2(x+2\sqrt{2})+\sqrt{2}(x+2\sqrt{2})

=(x+\sqrt{2})(x+2\sqrt{2} )

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