Factorise, x ² + 3√3x +6
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Answer:
x²+3√3x+6 = (x+2√3)(x+√3)
Given quadratic expression:
x²+3√3x+6
Splitting the middle term, we get
=x²+2√3x+√3x+6
= x²+2√3x+√3x+2×√3×√3
= x(x+2√3)+√3(x+2√3)
= (x+2√3)(x+√3)
x²+3√3x+6 = (x+2√3)(x+√3)
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