factorise x^2+3root 3x+6
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x²+3√3x+6
x²+2√3x+√3x+6=0
x(x+2√3)+√3(x+2√3)=0
(x+√3)(x+2√3)=0
x= -√3, x= -2√3
x²+2√3x+√3x+6=0
x(x+2√3)+√3(x+2√3)=0
(x+√3)(x+2√3)=0
x= -√3, x= -2√3
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here's your ans......
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