Math, asked by NotIncorecc, 10 months ago

factorise x^2+3x-180​

Answers

Answered by jaronronialbert
4

Factoring  x2+3x-180  

The first term is,  x2  its coefficient is  1 .

The middle term is,  +3x  its coefficient is  3 .

The last term, "the constant", is  -180  

Step-1 : Multiply the coefficient of the first term by the constant   1 • -180 = -180  

Step-2 : Find two factors of  -180  whose sum equals the coefficient of the middle term, which is   3 .

     -180    +    1    =    -179  

     -90    +    2    =    -88  

     -60    +    3    =    -57  

     -45    +    4    =    -41  

     -36    +    5    =    -31  

     -30    +    6    =    -24  

     -20    +    9    =    -11  

     -18    +    10    =    -8  

     -15    +    12    =    -3  

     -12    +    15    =    3    That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  -12  and  15  

                    x2 - 12x + 15x - 180

Step-4 : Add up the first 2 terms, pulling out like factors :

                   x • (x-12)

             Add up the last 2 terms, pulling out common factors :

                   15 • (x-12)

Step-5 : Add up the four terms of step 4 :

                   (x+15)  •  (x-12)

            Which is the desired factorization

Answered by sajidaliakhondi661
6

Answer:

(x-12)(x+15)

Step-by-step explanation:

x^2+15x-12x-180=0

x(x+15)-12(x+15)=0

(x-12)(x+15)=0

x=12. or. x=-15

solution set {-15,12}

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