Question

Factorise
(x^2-3x)(x^2-3x+7)+10​

Answer 1

Answer:

(x²-3x)(x²-3x+7)+10

X⁴-3x³+7x²-3x³+9x²+21x +10

X⁴-6x³+16x²+21x+10

Answer 2

${x}^{2} - 3x - 10 = (x - 5)(x + 2)$

Given

${x}^{2} - 3x - 10$

find a pair of factors of 10 which differ by 3.

The pair 5,2 works in that 5 . 2 = 10 and 5 - 2 = 3

Hence we find,

${x}^{2} - 3x - 10 = (x - 5)(x + 2)$

hooe this will help you...