Question

factorise x^2+7x+12=0

Answer 1

x^2+7x+12=0

x^2+4x+3x+12=0

X(X+4)+3(X+4)=0

(X+3)(X+4)=0

X+3=0. X+4=0

X= -3. X= -4

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Answer 2

Answer:

x^2+7x+12=0

=x^2+4x+3x+12=0

=x(x+4)+3(x+4)=0

=(x+3)(x+4)=0

x+3=0 or x+4=0

x=-3 or x=-4