factorise x^2+9√3x+42
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x^2+9√3x+42
x^2+(7√3x + 2√3x ) + 42
(x^2+ 7√3x) + (2√3x + 42)
x (x+7√3) + 2√3 (x+ 7√3)
(x+ 7√3) (x+2√3)
x^2+(7√3x + 2√3x ) + 42
(x^2+ 7√3x) + (2√3x + 42)
x (x+7√3) + 2√3 (x+ 7√3)
(x+ 7√3) (x+2√3)
aarondaviddon20:
how did you get (7√3x+2√3x)
because we need such factor of 42 ,,whose sum =9√3
so we factor 42 in terms of 7√3×2√3 ,,,,,,,because sum of 7√3+2√3=9√3
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1
Answer:
x^2+9√3x+42
=9x^2+3x+42
=12x^3+42=54x^4
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