Question

factorise x^2-(root2+1)x+root2​

Answer 1

Answer:

x=√2,1

Step-by-step explanation:

x²-(√2+1)x+√2=0

x²-√2x-x+√2=0

x(x-√2)-1(x-√2)=0

x-1=0,x-√2=0

x=1,√2