Question

factorise:-(x+2)(x-3)(x-2)+64 plzz answer fast

Answer 1

Solution:-

given by:-

$(x + 2)(x - 3)(x - 2) + 64 \\ ( {x}^{2} - {y}^{2} )(x - 3) + 64 \\ {x}^{3} - 3 {x}^{2} - x {y}^{2} - 3 {y}^{2} + 64$