find 'a' and 'b' it 5 + 2 √3 by 7 + 4 √3 = a + b √3
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Answered by
14
Heya !!!
Solution:- 5 + 2✓3 / 7 + 4✓3 = A + B✓3
LHS = 5+2✓3/7+4✓3
Rationalizing the denominator 7 + 4✓3
=> 5 + 2✓3 / 7 + 4✓3 × 7 - 4✓3/ 7 -4✓3
=> ( 5 + 2✓3) ( 7 - 4✓3) / ( 7 + 4✓3)(7-4✓3)
=> 5( 7 - 4✓3) + 2✓3( 7 - 4✓3) / (7)² - (4✓3)²
=> 35 - 20✓3 + 14✓3 - 24 / 49 - 48
=> 35 - 24 - 20✓3 + 14✓3/1
=> 11 - 20✓3 +14✓3
=> 11-6✓3
Now,
LHS = RHS
11 - 6✓3 = A + B✓3
Clearly,
A = 11 and B = -6
HOPE IT WILL HELP YOU...... :-)
Solution:- 5 + 2✓3 / 7 + 4✓3 = A + B✓3
LHS = 5+2✓3/7+4✓3
Rationalizing the denominator 7 + 4✓3
=> 5 + 2✓3 / 7 + 4✓3 × 7 - 4✓3/ 7 -4✓3
=> ( 5 + 2✓3) ( 7 - 4✓3) / ( 7 + 4✓3)(7-4✓3)
=> 5( 7 - 4✓3) + 2✓3( 7 - 4✓3) / (7)² - (4✓3)²
=> 35 - 20✓3 + 14✓3 - 24 / 49 - 48
=> 35 - 24 - 20✓3 + 14✓3/1
=> 11 - 20✓3 +14✓3
=> 11-6✓3
Now,
LHS = RHS
11 - 6✓3 = A + B✓3
Clearly,
A = 11 and B = -6
HOPE IT WILL HELP YOU...... :-)
gaurav504:
complete answer he ye
Answered by
5
5+2√3/7+4√3
= 5+2√3/7+4√3×7-4√3/7-4√3
= (5+2√3)(7-4√3)/(7+4√3)(7-4√3)
= 35-20√3+14√3-24/(7)^2-(4√3)^2
= 11-6√3/49-48
= 11-6√3 = a+b√3
a = 11 and b = -6. (On comparing the coefficient)
= 5+2√3/7+4√3×7-4√3/7-4√3
= (5+2√3)(7-4√3)/(7+4√3)(7-4√3)
= 35-20√3+14√3-24/(7)^2-(4√3)^2
= 11-6√3/49-48
= 11-6√3 = a+b√3
a = 11 and b = -6. (On comparing the coefficient)
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