Question

factorise x^2+y^2+2(xy-yz-zx)

Answer 1

x²+y²+2(xy-yz-zx)
x²+y²+2xy-2yz-2zx
(x²+y²+2xy)-(2yz+2zx)
(x+y)²-2z(y+x). (x²+y²+2xy = (x+y)² )
taking (x+y) common

(x+y)(x+y-2z)
hope this helps

Answer 2

Answer:

Step-by-step explanation:

x²+y²+2(xy-yz-zx)

x²+y²+2xy-2yz-2zx

(x²+y²+2xy)-(2yz+2zx)

(x+y)²-2z(y+x). (x²+y²+2xy = (x+y)² )

taking (x+y) common

(x+y)(x+y-2z)