Question

factorise x(2x+5)-25​

Answer 1

Step-by-step explanation:

x(2x+5)-25

2x²+5x-25

2x²+(10-5)x-25

2x²+10x-5x-25

2x(x+5)-5(x+5)

(2x-5)(x+5)

therefore

x=5/2 or x= -5

Answer 2

Step-by-step explanation:

x(2x+5)-25

=》2x^2+5x-25 =0.

The first term is,  2x^2   its coefficient is  2 .

The middle term is,  +5x  its coefficient is  5 .

The last term, "the constant", is  -25 

Step-1 : Multiply the coefficient of the first term by the constant   2 • -25 = -50 

Step-2 : Find two factors of  -50  whose sum equals the coefficient of the middle term, which is   5 .

-5   +   10   =   5   That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  -5  and  10 

=》2x^2 - 5x + 10x - 25=0.

=》x(2x-5)5(2x-5)

=》(x+5)(2x-5)=0.

=》x+5=0 or 2x-5=0.

=》x=-5 or 2x=5

=》x=-5 or x=5/2.