Question

Factorise:
(x+2y)(x-2y)(x²+4y²)​

Answer 1

$\huge\red{\ddot\smile}$ QUESTION

(x+2y)(x-2y)(x²+4y²)

Answer:-

=[(x)²+(2y)²][x²+4y²]

=[x²-4y²][x²+4y²]

=[(x²)²-(4y²)²]

=x⁴-16y⁴

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Answer 2

$\huge \boxed{answer}$

$\large{ \bold{(x - 2y)(1 - x - 2y)}}(x−2y)(1−x−2y)$

Step by step explanation:-

$</p><p>x - 2y - {x}^{2} + 4 {y}^{2}x−2y−x2+4y2</p><p>= x - 2y - ( {x}^{2} - 4 {y}^{2} )=x−2y−(x2−4y2)</p><p>= (x - 2y) - ( {x}^{2} - 2xy + 2xy + 4 {y}^{2} )=(x−2y)−(x2−2xy+2xy+4y2)</p><p>= (x - 2y) - (x(x - 2y) + 2y(x - 2y))=(x−2y)−(x(x−2y)+2y(x−2y))</p><p>= (x - 2y) - (x - 2y)(x + 2y)=(x−2y)−(x−2y)(x+2y)</p><p>= (x - 2y)(1 - (x + 2y))=(x−2y)(1−(x+2y))</p><p>= (x - 2y)(1 - x - 2y)=(x−2y)(1−x−2y)</p><p>$