Factorise x^3-1-3x^3+3x
Answers
Answered by
0
Answer:
Given x3 + 1/x3 + 3x + 3/x This can be re-written as shown x3 + 1/x3 + 3x2 × (1/x) + 3 × (x) × (1/x) This is in the form of a3 + b3 +3a2b + 3ab2 = (a + b)3 Hence, x3 + 1/x3 + 3x2 × (1/x) + 3 × (x) × (1/x) = (x + 1/x)3
Similar questions