Question

Factorise x^3+1 pls give it fast i am going out of time pls help me

Answer 1

Rewrite 11 as 1313.

x3−13x3-13

Since both terms are perfect cubes, factor using the difference of cubes formula, a3−b3=(a−b)(a2+ab+b2)a3-b3=(a-b)(a2+ab+b2) where a=xa=x and b=1b=1.

(x−1)(x2+x⋅1+12)(x-1)(x2+x⋅1+12)

Simplify.

Tap for fewer steps...

Multiply xx by 11.

(x−1)(x2+x+12)(x-1)(x2+x+12)

One to any power is one.

(x−1)(x2+x+1)

Answer 2

Answer:

(x+1)($x^{2} - x +1$)

Step-by-step explanation:

because : ($x^{3}+y^{3} = (x^{2} - xy + y^{2} )$)