Factorise x^3+1/x^3-2-3x+1/x
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Given,
x³+1/x³-2-3x+1/x
Calculation,
= x³+1/x³-2-3x+1/x
=x×(x³+1)-(x³-2)×(3x+1)/x×(x³-2)
=x^4+x-(3x^4+x³-6x-2)/x^4-2x
=x^4+x-3x^4-x³+6x-2/x^4-2x
= -2x^4+7x-x³+2/x^4-2x
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Answer=> -2x^4+7x-x³+2/x^4-2x
x³+1/x³-2-3x+1/x
Calculation,
= x³+1/x³-2-3x+1/x
=x×(x³+1)-(x³-2)×(3x+1)/x×(x³-2)
=x^4+x-(3x^4+x³-6x-2)/x^4-2x
=x^4+x-3x^4-x³+6x-2/x^4-2x
= -2x^4+7x-x³+2/x^4-2x
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Answer=> -2x^4+7x-x³+2/x^4-2x
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