Math, asked by potdaraayush9p3cgj0, 1 year ago

Factorise
x^3-1÷x^3-2x+2÷x

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Answered by pariangel1

${x}^{3} - 1 \div {x}^{3} - 2x + 2 \div x \\ = ({x}^{3} - 1 \div {x}^{3}) - 2(x - 1 \div x) \\ = (x - 1 \div x)( {x}^{2} + x \times 1 \div x + 1 \div {x}^{2} ) - 2(x - 1 \div x) \\ = (x - 1 \div x)( {x}^{2} + 1 + 1 \div {x}^{2} - 2) \\ = (x - 1 \div x)( {x}^{2} - 1 + 1 \div {x}^{2} )$

potdaraayush9p3cgj0: yes

pariangel1: I don't know how to do it

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potdaraayush9p3cgj0: u copied it from somewhere right??

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