Question

Factorise x 3 - 23x 2 + 142x - 120

Answer 1

find the factor of divisor
see first use the remainder theorem..



and factorise it



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Answer 2

Answer:

The answer is (x-1) (x-10) (x-12)    

Step-by-step explanation:

Given problem

Factorize x³ - 23 x² + 142 x - 120

Rewrite the given equation as given below

           x³- x² - 22 x² + 22 x + 120 x - 120

           x²(x - 1) -22x(x -1) + 120(x-1)  

 take (x-1) common  

           (x-1) [ x² - 22x + 120 ]    

-22x can be written as  -10x - 12x

           (x-1) [ x² - 10x -12x + 120 ]  

           (x-1) [ x(x - 10) -12(x-10) ]

           (x-1) [ (x-10) (x-12) ]

           (x-1) (x-10) (x-12)