Factorise : x 3 - 23x 2 + 142x - 120
Answers
x3 - 23x2 +142x -120
If we put x=1 the value of the expression becomes zero.
Thus by the factor theorem (x-1) is a factor of the given polynomial.
The polynomial is a 3 degree polynomial and hence has 3 factors.
To get the other 2 factors divide the given polynomial by (x-1) and factorize the 2 degree polynomial obtained by middle term splitting.
Answer:
We know that if the sum of the coefficients is equal to 0 then (x-1) is one of the factors of given polynomial.
x-1 = 0
x = 1
Put x=1,
(1)³-23(1)²+142(1)-120
→ 1-23+142-120
→ 120-120
→ 0
Therefore,(x-1) is a factor of the given polynomial.
Now the factors are (x-1) and (x²-22x+120) {see pic for knowing how (x²-22x+120) is a factor}
Now factorise x²-22x+120
x²-22x+120
→ x²-12x-10x+120
→ x(x-12)-10(x-12)
→ (x-12)(x-10)
Therefore, x²-22x+120 = (x-12)(x-10)
The factors of x³-23x²+142x-120 = (x-1)(x-12)(x-10)
Hope it helps....…