factorise x^3-23x^2+142x-120
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Answer:
(x - 1)(x - 10)(x - 12)
Step-by-step explanation:
Given Equation is x³ - 23x² + 142x - 120
= x³ - x² - 22x² + 22x + 120x - 120
= x²(x - 1) - 22x(x - 1) + 120(x - 1)
= (x - 1)(x² - 22x + 120)
= (x - 1)(x² - 12x - 10x + 120)
= (x - 1)[x(x - 12) - 10(x - 12)]
= (x - 1)(x - 10)(x - 12)
Hope it helps!
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