Question

factorise x^3-2x^2-5x+6

Answer 1

now we have another 2 methods

$(x - 1)( {x }^{2} - x - 6) \\ (x - 1)(x {}^{2} - 3x + 2x - 6) \\ (x - 1)(x(x - 3) + 2(x - 3)) \\ (x - 1)(x - 3)(x + 2)$

Answer 2

Concept:

Algebraic expressions called polynomials include coefficients and variables. Indeterminates are another name for variables. For polynomial expressions, we can do mathematical operations like addition, subtraction, multiplication, and positive integer exponents, but not division by variable. x²+x-12 is an illustration of a polynomial with a single variable. There are three terms in this example: x², x, and -12.

The product of a polynomial's factors with degrees that are less than or equal to the original polynomial can be used to represent a polynomial. Factorization of polynomials is the technical term for the factoring process.

Prime factorisation is the one of its method

Given:

x³-2x²-5x+6

Find:

Factorise x³-2x²-5x+6

Solution:

x³-2x²-5x+6

=(x-1)(x²-x-6)

=(x-1)(x²-3x+2x-6)

=(x-1)(x+2)(x-3)

Therefore, factorisation of x³-2x²-5x+6 is (x-1)(x+2)(x-3)

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