Question

factorise x^3-2x^2-5x+6 by zero method.​

Answer 1

Answer:

216

Step-by-step explanation:

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Answer 2

Answer:

Let

f(x)=x3−2x2−5x+6

As of coefficient is 0 so x=1 is a zero of f(x)

f(1)=1-2-5+6 = 0

divide f(x) by (x-1)

f(x) = x3 - 2x2 -5x +6

= (x -1)(x2 - x - 6)

Then, x2 - x -6 = (x - 3)(x + 2)

So, the other 2 roots of f(x) = 0 are x= 3 and x= -2

Hope this helps ✌️