Question

factorise x^3- 2x^2 -x +2 by using factor theorum​

Answer 1

Answer:

${x}^{3} - 2 {x}^{2} - x + 2 \\ = {x}^{3} - {x}^{2} - {x}^{2} + x - 2x + 2 \\ = {x}^{2}(x - 1) - x(x - 1) - 2(x - 1) \\ = (x - 1)( {x}^{2} - x - 2)$