Question

factorise x^3 - 2x^2-x+2
fast

Answer 1

Here is your answer
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x^3−2x^2−x+2

=x^3−x−2x^2+2

=x(x^2−1)−2(x^2−1)

=(x^2−1)(x−2)






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therefore answer :- (x^2−1)(x−2)

Answer 2

x³ -2x² -x+2

Taking common,

x²(x-2) -1(x-2)

(x² -1)(x-2)
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If it is equal to 0,

(x²-1)(x-2) =0

x²-1 =0 OR x-2=0

x²=1 OR x=2

x=√1 =1 OR x =2

Hence, the possible values of x are :-

1 and 2, only if they are equal to 0