factorise: x^3-3x-1+3÷x-1÷x^3
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p(x) = given polynomial
= x⁶ - 3 x⁴ - x³ + 3 x² - 1
= (x² + x - 1) (x⁴ - x³ - x² + x +1)
x² + x -1 has two real roots: (√5 - 1) /2 and -(√5 +1)/2
There are 4 imaginary roots for the polynomial.
= x⁶ - 3 x⁴ - x³ + 3 x² - 1
= (x² + x - 1) (x⁴ - x³ - x² + x +1)
x² + x -1 has two real roots: (√5 - 1) /2 and -(√5 +1)/2
There are 4 imaginary roots for the polynomial.
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