FACTORISE x^3+3x^2+3x+1
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Using the rational root theoerm gives...
p=1 & q=-1
All values of +p/q are -1 & 1
(1)^3+3(-1)^2+3(-1) +1
-1+3-3+1=0
therefore x=-1
(1)^3+3(1)^2+3(1) +1
1+3+3+1
=8
therefore not a root at x=1
Divide the polynomial by (x+1)
x^3+3x^3+3x+1/x+1
x^3+x^2+x^2x+x^2x+x+1/x+1
(x^3+x^2) +(x^2+x) +(x^2+x) +(x+1) /x+2
(x^2+x+x+1)
x^2+2x+1
Final answer is (x+1) (x+1) ^2=(x+1) ^3.....
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