Question

factorise: x^3_3x^2_9x_5​

Answer 1

Answer:

HEY MATE HERE IS YOUR ANSWER

p[x] = x3-3x2-9x-5 p[-1] = [-1]3-3[-1]2-9[-1]-5 = -1-3+9-5 = 0 ... (x+1) is a factor of p[x]. Now divide x3-3x2-9x-5 by x+1. And the quotient will be-: x2-4x-5 = x2+5x-x-5 = x(x+5)-1(x+5) = (x+5)(x-1) ... (x+5)&(x-1) is also a factor of p[x] Hence, (x+1),(x+5)&(x-1) are the factors of p[x].

HENCE,(X+1)(X-5)(X-1) IS THE ANSWER..

HOPE IT HELPS YOU..

PLEASE MARK IT AS THE BRAINLIEST ANSWER..

Answer 2

Step-by-step explanation:

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