Math, asked by hetalgondaliya0, 1 year ago

factorise x^3+8x^3-64z^3+24xyz

Answers

Answered by SakshamMahajan007
0
Hey Future Mathematicians,

Answer is in the attachment above.

Thanks!!
Attachments:

hetalgondaliya0: It is 24 xyz not 2xyz
SakshamMahajan007: Yeah sorry please consider it 24xyz only
hetalgondaliya0: But how can it be (x+y+z)^3
hetalgondaliya0: It is not a^3+b^3+3a^2b+3ab^2
Answered by Anonymous
2

Answer:

 \sf \: x^3−8y^3−64z^3−24xyz \\  \\\sf \: a^3+b^3+c^3−3abc \\ \\  \sf=(a+b+c) \\ \\\sf(a^2+b^2+c^2−ab−bc−ca)

Comparing with the expression of standard formulae,

Here,

 \sf \: a=x \\  \\  \sf \: b=−2y \\  \\ \sf \: c=−4z \\  \\ \sf \: Therefore, \\  \\\sf=>x^3+(−2y)^3+(−4z)^3−3(x) \sf(−2y)(−4z) \\  \\  \sf=(x−2y−4z) \\  \\\sf(x^2+4y^2+16z^2+2xy−8yz+4xz)

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