Question

factorise( x-3y)^3+ (3y -2z)^3+(2z-x)^3

Answer 1

x-3y + 3y-2z + 2z-x,

0,

since

(x-3y)+(3y-2z)+(2z-x)=0,

therefore

(x-3y)³+(3y-2z)³+(2z-x)³

=3×(x-3y)(3y-2z)(2z-x)

Answer 2

See the photo for your answer.

HOPE IT HELPS YOU.