Question

factorise (x+4)² - 5xy - 20y - 6y2​

Answer 1

Answer:

(X +4 -3y)(X+4-2y)

Step-by-step explanation:

( X+4)²-5xy-20y-6y²

=>(X+4)-5y(X+4)-6y²

let , (X+4) be a

a² -5ya- 6y²

=> a² -3ya -2ya -6y²

=> a(a-3y) - 2y(a-3y)

=> (a-3y)(a-2y)

putting the value of a in the equation we get :

(X+4-3y)(X+4-2y)