Question

Let Q =x^2-x-6=0 ,X belongs to natural number, then find the set of Q
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Answer 1

Answer:

x^2-x-6=0

x^2-3x+2x-6=0

x(x-3)+2(x-3)=0

(x-3)(x+2)=0

either x-3=0 or x+2=0

x=3 x=-2