Factorise x^4-7x^3+9x^2+7x-10
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Step-by-step explanation:
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Answer: Factorization of x^4-7x^3+9x^2+7x-10 is (x-1)(x+1)(x-5)(x-2)
Step-by-step explanation:
x⁴ - 7x³ + 9x² + 7x - 10 = 0
x⁴ - x³ - 6x³ + 6x² + 3x² + 7x - 10 = 0
x³(x-1) - 6x²(x - 1) + 3x² - 3x + 10x - 10 = 0
x³(x-1) - 6x²(x - 1) + 3x(x - 1) + 10 (x - 1) = 0
(x-1) [ x³ - 6x² + 3x + 10 ] = 0
(x-1) [ x³ + x² - 7x² + 3x + 10 ] = 0
(x-1) [ x²(x+1) - 7x² + 3x + 10 ] = 0
(x-1) [ x²(x+1) - 7x² -7x + 10x + 10 ] = 0
(x-1) [ x²(x+1) - 7x(x+1) + 10(x+1) ] = 0
(x-1)(x+1) [ x² -7x + 10 ] = 0
(x-1)(x+1) [ x² -5x -2x + 10 ] = 0
(x-1)(x+1) [ x(x -5) -2(x-5) ] = 0
(x-1)(x+1)(x-5)(x-2)
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