Question

factorise
(x + 4) (x-2)2(x-8) - 37​

Answer 1

(x^2-x)^2-8 (x^2-x)+12

ʟᴇᴛ x^2-x=ʏ

ᴛʜᴇɴ,

ʏ^2-8ʏ+12

=> ʏ^2-6ʏ-2ʏ+12

=> ʏ (ʏ-6)-2 (ʏ-6)

=> (ʏ-6)(ʏ-2)

ᴘᴜᴛᴛɪɴɢ ᴛʜᴇ ᴠᴀʟᴜᴇ ᴏꜰ ʏ

=> (x^2-x-6)(x^2-x-2)

=> (x^2-3x+2x-6)(x^2-2x+x-2)

=> [x (x-3)+2 (x-3)][x (x-2)+1 (x-2)]

=> (x-3)(x+2)(x-2)(x+1).

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Answer 2

Answer:

ok

thank you

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Step-by-step explanation:

x^2-x)^2-8 (x^2-x)+12

ʟᴇᴛ x^2-x=ʏ

ᴛʜᴇɴ,

ʏ^2-8ʏ+12

=> ʏ^2-6ʏ-2ʏ+12

=> ʏ (ʏ-6)-2 (ʏ-6)

=> (ʏ-6)(ʏ-2)

ᴘᴜᴛᴛɪɴɢ ᴛʜᴇ ᴠᴀʟᴜᴇ ᴏꜰ ʏ

=> (x^2-x-6)(x^2-x-2)

=> (x^2-3x+2x-6)(x^2-2x+x-2)

=> [x (x-3)+2 (x-3)][x (x-2)+1 (x-2)]

=> (x-3)(x+2)(x-2)(x+1).