Factorise ....
(x-5)^2-5(x-25)-24
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Hello friend
__________________________
===> (x -5)^2 -5(x -25) -24
==> (x-5)^2 - 5(x - 5) -24
x -5 = y taking
==> (y)^2 - 5y - 24
==> y^2 -8y+ 3y -24
==> y(y- 8)+ 3( y - 8)
==> ( y -8 ) (y + 3)
Now, substitute the value of y with x -5
==>. ( x - 5 - 8) (x - 5 + 3)
==> (x + 13 ) ( x - 2 )
This is the solution for the equation.
Thanks..
:)
__________________________
===> (x -5)^2 -5(x -25) -24
==> (x-5)^2 - 5(x - 5) -24
x -5 = y taking
==> (y)^2 - 5y - 24
==> y^2 -8y+ 3y -24
==> y(y- 8)+ 3( y - 8)
==> ( y -8 ) (y + 3)
Now, substitute the value of y with x -5
==>. ( x - 5 - 8) (x - 5 + 3)
==> (x + 13 ) ( x - 2 )
This is the solution for the equation.
Thanks..
:)
niti13:
Hello .... i have a doubt .
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