CBSE BOARD XII, asked by Ninja444, 1 year ago

Factorise ....

(x-5)^2-5(x-25)-24

Answers

Answered by Rajusingh45
7
Hello friend

__________________________


===> (x -5)^2 -5(x -25) -24

==> (x-5)^2 - 5(x - 5) -24

x -5 = y taking

==> (y)^2 - 5y - 24

==> y^2 -8y+ 3y -24

==> y(y- 8)+ 3( y - 8)

==> ( y -8 ) (y + 3)

Now, substitute the value of y with x -5


==>. ( x - 5 - 8) (x - 5 + 3)

==> (x + 13 ) ( x - 2 )


This is the solution for the equation.


Thanks..

:)

niti13: Hello .... i have a doubt .
niti13: Answer ke second step main 25 kii jgah 5 kaise aaya??
Rajusingh45: I have taken common multiple of 25
Rajusingh45: MEANS 5 x 5 = 25 we can use this instead of 25
niti13: Okkk ...thanks .
niti13: But last main x+13 kii jgh x-13 aaeyga ??
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