Factorise x^6+5x^3+8
Answers
Answered by
3
let x^3=t
(x^3)^2+5(x^3)+8=0
t^2+5t+8=0
but you have to see
D=b^2-4ac<0
hence ,
roots not be real .roots is imaginary .
hence for real roots
factorisation of x^6+5x+8 is not possible .
(x^3)^2+5(x^3)+8=0
t^2+5t+8=0
but you have to see
D=b^2-4ac<0
hence ,
roots not be real .roots is imaginary .
hence for real roots
factorisation of x^6+5x+8 is not possible .
Answered by
0
hope this helps.....
pls mark it as the brainliest.....
pls mark it as the brainliest.....
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anveshsawarn:
4×8=32 not 24
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