factorise x^8+y^8 as real quadratic factor.
salonidarji2004:
Are u sure it is addition because it should be subtraction as per my knowledge
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x^8-y^8=(x⁴)²-(y⁴)²
=(x⁴+y⁴)(x⁴-y⁴)
=(x⁴+y⁴)(x²-y²)(x²+y²)
=(x⁴+y⁴)(x²+y²)(x+y)(x-y)
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=(x⁴+y⁴)(x⁴-y⁴)
=(x⁴+y⁴)(x²-y²)(x²+y²)
=(x⁴+y⁴)(x²+y²)(x+y)(x-y)
I THINK IT WILL HELP U
PLS MARK IT AS BRAINLIEST
pls mark it as brainliest
Hey buddy this answer I too knw bt check the question
It is addition
its wrong
i asked as real quadratic factor
i got answer
Answered by
1
using( a^2-b^2 ) identity!!
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i asked as real quadratic factor
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