Which of the following has the largest number of atoms?(I NEED THE STEPS OF CALCULATION)
*0.5g atom of Cu
*10^23 atoms of Cu
*0.623 g atom of Cu
*3.175 gram of Cu.
Please i need the steps!!!!
Answers
Answered by
61
★ 0.5g atom of cu
means mole of cu = 0.5
no of atoms = mole × Avogadro's constant =0.5 × 6.023 × 10^23 = 3.0115×10^23
★ 10^23 atoms of cu
★ 0.623 g atoms cu
so, no of mole = 0.623
no of atoms = mole × Avogadro's constant =0.623× 6.023×10^23
= 3.752 × 10^23
★3.175 g of cu
mole = given wt/atomic wt
=3.175/63.5 = 1/50 = 0.02
no of atoms = 0.02 × 6.023× 10^23
= 0.12046 × 10^23
here you can see that no of atoms largest in 0.623 g atom of cu .
means mole of cu = 0.5
no of atoms = mole × Avogadro's constant =0.5 × 6.023 × 10^23 = 3.0115×10^23
★ 10^23 atoms of cu
★ 0.623 g atoms cu
so, no of mole = 0.623
no of atoms = mole × Avogadro's constant =0.623× 6.023×10^23
= 3.752 × 10^23
★3.175 g of cu
mole = given wt/atomic wt
=3.175/63.5 = 1/50 = 0.02
no of atoms = 0.02 × 6.023× 10^23
= 0.12046 × 10^23
here you can see that no of atoms largest in 0.623 g atom of cu .
PrincessManshi:
but the right ans is 0.5
Answered by
17
The correct answer is 0.623 g atom has more atom of cu
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