Question

Factorise : x – 9 + 9zy – xyz

Answer 1

solution, x-9+9zy-xyz

=-(9-x)+yz(9-x)

=(9-x)(1-yz)

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Answer 2

$\large\underline{\bold{Given \:Question - }}$

$\sf \: Factorise \: : \: x - 9 + 9zy - xyz$

$\large\underline{\bold{Solution-}}$

Concept Used :-

1. Method of Common Factors

• In this method, we have to write the irreducible factors of all the terms

• Then find the common factors amongst all the irreducible factors.

• The required factor form is the product of the common term we had chosen and the left over terms.

2. Factorisation by Regrouping Terms

• Sometimes it happens that there is no common term in the expressions then

• We have to make the groups of the terms.

• Then choose the common factor among these groups.

• Find the common binomial factor and it will give the required factors.

Let's solve the problem now!!

$\rm :\longmapsto\:x - 9 + 9zy - xyz$

$\rm :\longmapsto\:(x - 9) + yz(9 - x)$

$\rm :\longmapsto\:(x - 9) - yz(x - 9)$

$\rm :\longmapsto\:(x - 9)(1 - yz)$