Factorise x cube _23x square + 142 x - 120
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©x^3 - 23x^2 + 142x - 120
=x^3 - 22x^2 - x^2 + 120x + 22x - 120
=x^3 -22x^2 -x^2 + 22x + 120x - 120
=x^3 - 10x^2 -12x^2 -x^2 +10x+ 12x + 120x -120
=x^3 - x^2 - 10x^2 +10x -12x^2 +12x +120x -120
=x^2(x -1) -10x(x - 1) -12x(x - 1) +120(x - 1)
= (x -1) (x^2 -10x- 12x +120 )
=(x -1) {x(x - 10) -12( x - 10 ) }
=(x -1) (x -10 )( x -12)
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Your Answer: (x -1 )( x - 10) (x - 12)
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=x^3 - 22x^2 - x^2 + 120x + 22x - 120
=x^3 -22x^2 -x^2 + 22x + 120x - 120
=x^3 - 10x^2 -12x^2 -x^2 +10x+ 12x + 120x -120
=x^3 - x^2 - 10x^2 +10x -12x^2 +12x +120x -120
=x^2(x -1) -10x(x - 1) -12x(x - 1) +120(x - 1)
= (x -1) (x^2 -10x- 12x +120 )
=(x -1) {x(x - 10) -12( x - 10 ) }
=(x -1) (x -10 )( x -12)
_____________________________
Your Answer: (x -1 )( x - 10) (x - 12)
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