factorise: x cube - 23x square+ 142x - 120
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Answer:
x³ - 23x² + 142x - 120
try first x = 1
1 - 23 + 142 - 120 = 0
So it worked
So (x-1) is one factor of x³ - 23x² + 142x - 120. Now do long division method to find other factors
x² - 22x + 120
x - 1 ∫ x³ - 23x² + 142x - 120
- x³ - ⁻ x²
- 22x² + 142x
- ⁻22x² - 22x
120x - 120
120x - ⁻ 120
0
Now we got x² - 22x + 120 = x² - 10x - 12x -+ 120 = x (x - 10) - 12(x - 120)
(x- 10) (x - 12)
Read more on Brainly.in - https://brainly.in/question/5937841#readmore
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