factorise x cube + 6 X square + 11 x + 6 by factor theorem
Answers
Given : x³ + 6x² + 11x + 6
To Find : Factorize
Solution:
x³ + 6x² + 11x + 6
P(x) = x³ + 6x² + 11x + 6
P(0) = 6
P(1) = 24
P(-1) = -1 + 6 - 11 + 6 = 0
=> (x + 1) is one of the factor
x² + 5x + 6
x + 1 _| x³ + 6x² + 11x + 6 |_
x³ + x²
__________
5x² + 11x + 6
5x² + 5x
__________
6x + 6
6x + 6
__________
0
x³ + 6x² + 11x + 6 = ( x + 1)(x² + 5x + 6)
=> x³ + 6x² + 11x + 6 = ( x + 1)(x + 2)(x + 3)
x³ + 6x² + 11x + 6 = ( x + 1)(x + 2)(x + 3)
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Answer:
Given : x³ + 6x² + 11x + 6
To Find : Factorize
Solution:
x³ + 6x² + 11x + 6
P(x) = x³ + 6x² + 11x + 6
P(0) = 6
P(1) = 24
P(-1) = -1 + 6 - 11 + 6 = 0
=> (x + 1) is one of the factor
x² + 5x + 6
x + 1 _| x³ + 6x² + 11x + 6 |_
x³ + x²
__________
5x² + 11x + 6
5x² + 5x
__________
6x + 6
6x + 6
__________
0
x³ + 6x² + 11x + 6 = ( x + 1)(x² + 5x + 6)
=> x³ + 6x² + 11x + 6 = ( x + 1)(x + 2)(x + 3)
x³ + 6x² + 11x + 6 = ( x + 1)(x + 2)(x + 3)