Question

factorise x cube + 64​

Answer 1

$= > \: \: {x}^{3} + 64 \\ \\ = > {(x)}^{3} + {(4)}^{3} \\ \\ = > (x + 4)( {x}^{2} + 16 - 4x ) \\ \\ = > (x + 4)( {x}^{2} - 4x + 16)$

${\text {\huge{Hence, }}}$

${ \boxed{ \boxed{ \red{{x}^{3} + 64 = (x + 4)( {x}^{2} - 4x + 16)}}}}$

$<marquee>MARK BRAINLIEST$

Answer 2

Answer:

x cube = - 64

x^1/3= -8

(x/64)^ 1/3 = 1^1/3

now cube root of 1 are 1 and (-1(+_) 3i)/2

now compare